Question

Over three vectors. Vector of magnitude 5.60 direction 8 - 46.0 above the positive rasis. Vector of magnitude 5.00 units a directed in the direction of the positive pas. Vector of magnitude 7.20 units direction - 55.0 dockwise from the negative Find the magnitude and direction of 2 - 3 magnitude direction counterclockwise from the ty X

Answer 1

S 18 5.6 46 TU 7-2 55 Á = 5.6 x cos46i +5.6 x sin46; À = 3.891 + 4.028; B = 5; Ć - -72x sin55i - 7.2 x cos55; č = - 5.898i - 4.13 2 A - B +3 C = 2 x (3.89i +4.028j) - 5j +3 x ( - 5.898i - 4.137) 2 A - B + 3 C = -9.914i - 9.3347 B +37 magnitude 27.5+58 V(-9.914)2 +(- 9.334)2 2 A - B +3 C = 13.617

9.914 O te +x oras 9,334 9.334 tan = 9.914 Angle is in third quadrant so add 180 degrees 0 = tan -1 9.334 9.914 180 A = 223.3° Counterclockwise from positive x axis