Question

below is a electrical circuit with 2 batteries and 3 resistors

13 7 R3 10 R₂ 4 12 1 R Write down the Kirchhoff Junction equation and solve it for I, in terms of I, and 13. Write the result here: Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise O- Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components 4. Ry, and R. 0- The resistors in the circuit have the following values . R.-20 - R13 n Solve for all the following (some answers may be negative) Amperes I, - Amperes I) - Amperes NOTE: For the equations, put in resistances and current SYMBOLICALLY using variables like RRR, and to Use numerical values of 10 and 4 for the voltages.

Answer 1

13 Rg lov A Rg 4v 19 pont a Applying R Kirchhoff Junction en at Ist Iz- Iz = = I, - 12-13 2

Iz # H3 ASH lov Applying Kirchoff's look egn Clowwise Riz 4 - IZR, – Ī, R, 20 2 qv HO. 10 + I2 R2 + Iz R₂ = 0 3 H I, RA 由) 2 and touches the Corner eph is also the Kirchhoff's a loop egh for a loop that starts at the lower left components AV, RI,R2

7 hiss Given R = 21 R22 dor R = 1354 from, en ② putting 1,2 12-13 4- 12 R2 - (12-13) R2.0 =4- 412 - 212 – 213 20 - 6I2 - 2 I3 = - 4 3 12 + 2₂ 22 from egn 412 + 1393 -10 5 11 Bell; SX3 9 X 4 - e que 1254 + 413 - 12/2 -39 1g 12t30 -3513 2 42 2-12A 13 2 dirn ( Griven current 12 = at 12 = 1.07 A Ijz 1707 + 1.2 42 35 must be reversed) ill = 2:27A