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A 2.0 kg block is sliding across a table with an initial speed of 0.5 m/s. The table imparts a 20.0 N force due to friction oA 2.0 kg block is sliding across a table with an initial speed of 0.5 m/s. The table imparts a 20.0 N force due to friction on the block. How much work in Joules will the table do on the block?

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Answer #1

d .) mm. -Jo masa before distance Let the block Sides a Stop. 20 block a the deauleration So and initial velocity no final ve1 F di Work done by the table. on the block W= -(20x0.013) 0.26 J w !! )

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