A system does 2500 J of work on the environment in the process, his internal energy...

Question

Question

science physics

Answer 1

Answer #1

W = 2500J

∆U = -1500J

From thermodynamics first law , ∆Q = ∆U + W

=) ∆Q = -1500 + 2500 = 1000 J

=) ∆Q = 1×10^3 J

Answer 2

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