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please answer a-c
(8%) Problem 7: A specific slide projector has a 100 mm focal length lens. Status re for view Completed Completed Completed 3
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Answer #1

a)

Slide projecters use convex lens. Here the focal length of the lens is given as 100 mm

Using Lens formula:

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

Taking right side of lens as positive and left side of lens as negative.

u = -120 mm (Since, object is being placed on left side of lens)

f = +100 mm (Focal length of convex lens is positive)

Substituting values:

\frac{1}{v} + \frac{1}{120} = \frac{1}{100}

\frac{1}{v} = \frac{1}{100} - \frac{1}{120}

\frac{1}{v} = \frac{120-100}{100*120}

\frac{1}{v} = \frac{20}{12000}

\frac{1}{v} = \frac{1}{600}

v = 600\ mm = 0.6\ m

So, the screen should be placed at a distance of 0.6 m from the lens on the right side to get a clear and bright image.

b)

Magnification in convex lens is given by: m = v/u, where v = image distance and u = object distance.

So, m = 600/-120 = -5, The negative sign indicates that the image will be inverted.

So, if object dimension is 24 by 36 mm, then image dimension = 5 * object dimension = 120 by 180 mm

So, the smaller dimension of image in metres = 0.12 m

c)

Also, the larger dimension of image in metres = 0.18 m

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