Question

The following circuit contains a 10 V battery, a 5 resistor, a 5 mH inductor, and a switch connected in series. What is the battery current immediately after the switch is closed? 512 w =10 V 5 mH 0000 Select one: a. O A b. 1 A c. 2 A d. 0.5 A

Answer 1

Given:

$V=10\ \text V\\ R=5\ \Omega\\ L=5\times10^{-3}\ \text H$

We close the switch at $t=0\ \text s$

Then, the current is,

$I=\frac{V}{R}(1-e^{-Rt/L})\\ =\frac{10}{5}(1-e^{-5\times0/(5\times10^{-3})})\ \text A\\ =0\ \text A$

Therefore, option a is the right answer.