Question

Using the data in the table, determine the rate constant of the reaction and select the appropriate units. Trial [A] (M) [B] (M) Rate (M/s) 0.320 0.280 0.0212 1 A + 2B - C +D 0.320 0.560 0.0212 0.0848 3 0.640 0.280 Units M-15-1

Answer 1

# Given reaction is - A + 2B C + D # From data table: when Concentration of a double rate becomes 4 times When concentration of B double sate remain unchanged therefore, the rate laws expression is - (by using data table result) K CAD? [80° rate values we putting we have - K [0.32072 [0.280] ° 0.0212 0.0212 K C0.320 ] ? x L = K - 0.0212 0.0212 12 (0.320] ² o.1024 K 0.207 Mall S

With the help of data table it is clear the reaction is overall second order reaction.

The rate constant for the reaction

k = 0.207 M^{​​​​​​-1} s^{​​​​​​-1}