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5. Assume the reaction is A+B 2C. If 50 mL of 1.00 M A and 50 mL of 1.00 B are added together, what is the concentration of C
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Answer #1

As per the equation-

1 mol A reacts with 1 mol B to produce 2 mol of C.

Now,

Moles of A = Molarity / Volume (L)

= 1*0.05 = 0.05 mol

Mol of B = 0.05 mol

Mol of A = 2* Mol of C

So,

Mol of C = 0.05 mol /2 = 0.025 mol

Thus,

Theoretical yield = 0.025 mol

% Yield = Actual Yield / Theoretical Yield * 100

40 = Actual Yield / 0.025 mol * 100

0.4 = Actual Yield / Theoretical Yield

Actual Yield =  0.01 mol

Now,

Total volume = 50+50 = 100 mL = 0.1 L

Concentration = 0.01 mol / 0.1 L = 0.1 M

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