As per the equation-
1 mol A reacts with 1 mol B to produce 2 mol of C.
Now,
Moles of A = Molarity / Volume (L)
= 1*0.05 = 0.05 mol
Mol of B = 0.05 mol
Mol of A = 2* Mol of C
So,
Mol of C = 0.05 mol /2 = 0.025 mol
Thus,
Theoretical yield = 0.025 mol
% Yield = Actual Yield / Theoretical Yield * 100
40 = Actual Yield / 0.025 mol * 100
0.4 = Actual Yield / Theoretical Yield
Actual Yield = 0.01 mol
Now,
Total volume = 50+50 = 100 mL = 0.1 L
Concentration = 0.01 mol / 0.1 L = 0.1 M
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Part 5 Finally, fill in the equilibrium concentrations: [A] (M) [B] (M) [C] (M) Initial 1.00 1.00 1.00 Change + 0.25 I+ 0.25 -0.50 Equilibrium Submit Anne Tries 0/99 Part 6 It is now possible to calculate K using the equilibriuri concentrations of A, B and C. K- Submit Answe Tries 0/99 In order to find the change in the concentrations of A, B and C, when they are allowed to react and come ta equilibrium, we need to be...
Equilibrium Concentrations -- A + B = 2C
At a particular temperature, K = 1.00×102
for the reaction:
H2(g) + F2(g)
2HF(g)
In an experiment, at this temperature, 1.00×10-1 mol
of H2 and 1.00×10-1 mol of F2 are
introduced into a 1.09-L flask and allowed to react. At
equilibrium, all species remain in the gas phase.
What is the equilibrium concentration (in mol/L) of
H2?
mol/L
1 pts
What is the equilibrium concentration (in mol/L) of HF?
mol/L
1 pts...
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The equilibrium constant Kc for the reaction: A(g) + B(g) ⇔ 2C(g) is 0.76 at 150 °C. If 0.500 M of A is added to 0.500 M of B in a 1.00 L container, calculate the [EQ] for A, B and C
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