Question

b. How does increasing the initial velocity of glider 1 change the final velocity?

c. Plot in the graph paper below the graph vf(m/s) versus v1,i(m/s) using the indicated scale.

d.Determine the slope of the function vf versus v1,i.

e.Compare the experimental slope found in the previous question with the theoretical slope from equation                                                                          ). Conclude

vi,1(m/s)	vi,2(m/s)	vf measured (m/s)
0.25	0	0.125
0.273	0	0.136
0.288	0	0.144
0.485	0	0.242
0.526	0	0.263

Added load m1(g)	Added load m2(g)	vi,1(m/s)	vi,2(m/s)	vf(m/s) measured	vf(m/s) calculated	Error % Vf,m- Vf,c Vf,c×100
0	0	0.462	0	0.245	0.231	6%
100	0	0.564	0	0.327	0.282	15%
140	40	0.478	0	0.268	0.239	12%
140	100	0.399	0	0.175	0.199	12%
100	140	0.273	0	0.134	0.136	1.74%
40	140	0.4502	0	0.201	0.225	10.6%
0	100	0.526	0	0.125	0.263	18.2%

Answer 1

By ave Momentum conservation Equation movi + m. Ut (m, 4 m2): 441-0 m, vit me uri m, tma Etteet 1994 m2) is then I final / velocity decresing And if m₂ =0 as mentioned in table) then Ug = m . Vito Increasing m, to then g = Vi re (final velocity initial wehtity if m, is decresing then to maintain conservation of momenturn egr D. Hence Usi increasing bif(m, m2) is deerning then ug final velocity) is increasing

1 0.175 VE amo 0.265 0.1607 0.155+ 0.1507 Slope - Avf 0.154-0.135 AVI 0.30 -0.26 0.145 AVE tano 0.1401 = m = 0.019 0.04 = 0.475 0,135 o.uzs AVEC 0.30 (Slop) Expernental maar ove - 0 0.125+ 0 Sexp= 0.48 0.25 0.30 0.35 0.40 0.45 0.50 Vli

By (eo) 0 m, if + m₂ N28 (m, tma) كه But ųf = 0 'n='m & m, & m₂ = m m Vi f Vj z by table =lo m2 = 140 mi m, tm2 m, Quo M = m m, ine Vf vff (stope) theoretical Sin quo 3 = 0.42 eq 8 Que & eq@ are nearly equal.