Calculate the mass of oxalic acid needed to make a 250.0 mL standard solution that is...
Calculate the mass of oxalic acid needed to make a 250.0 mL standard solution that is 0.0500 mol L-1 . You will use oxalic acid dihydrate, (COOH)2.2H2O. M((COOH)2.2H2O) = 126.07 g mol-1 )
Homework Answers
Solution-
suppose w gram oxalic acid needed.
Volume = 250ml =250× 10^-3L=0.25L
Molar mass = 126.07 gram/mole
Moles =w/126.07 mole
Molarity = moles/volume
=w/126.07×0.25
0.0500=w/31.52
w=0.0500×31.52
w=1.58 gram.
Hence, 1.58 gram required.
Add Answer to:
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You titrated a 22.00 mL solution of 0.0300 M oxalic acid with
freshly prepared solution of KMnO4. If it took 48.99 mL of this
solution, what is the molarity of the KMnO4?
0.022 L of 0.300 M oxalic acid
(0.022)(0.03) = 0.00066 mol oxalic acid
0.0006 mol oxalic acid x (2 mol KMnO4)/(5 mol oxalic acid)=
0.000264 mol KMnO4
0.000264 mol/0.04899 L = 0.05388855 M KMnO4
= 0.005388 M KMnO4
where did I go wrong?
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12. Describe how to prepare a 250mL 0.350M of oxalic acid solution using oxalic acid dihydrate solids (H2C204.2H20, molar mass = 126.06g/mol) You need to describe appropriate glassware in your preparation. 13. Describe how you would prepare 500. mL of 0.10M of HCl solution from 3.0M of HCI stock solution. You need to describe appropriate glassware in your preparation.
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