Question

Quantum Physics - Photon Momentum - Photon Scattering - Compton Effect 2 Photon Scattering by Electron - Compton Effect E = h' Ehf h (photon's momentum) 2 Before KW 2 After h 2-1=(1-cos) (Compton effect) m. = 2.43x10- Before After KEE E is between 0° and 180° The Planck constant is 6.626x10^-34 J s. The wavelength of the incident X-ray photon is unknown. The incident photon collides with the stationary electron. After the collision, the scattered photon's motion makes an angle 0 = 162.0° from the incident direction. The scattered photon's wavelength is 0.5947 nm, 1nm = 10° m. (a) Calculate the energy carried by the scattered photon. Write the result in terms of 10-16, J. Keep 4 decimal places. x10-16 Enter a number Submit (5 attempts remaining) (b) What is the incident pboton's wavelength in nm? Keep 4 decimal places. Enter a number nm Submit (5 attempts remaining) (c) What is the incident photon's momentum? Write the result in terms of 10-24 kg. m/s. Keep 3 decimal places. Enter a number x10-24kg . m/s Submit (5 attempts remaining) - 16 J. Keep 4 decimal places. (d) What is the incident photon's energy? Write the result in terms of 10 Enter a number x10-16 Submit (5 attempts remaining) (e) Calculate the kinetic energy carried by the electron after the collision (the recoiling electron). Write the result in terms of 10-16 J. Keep 4 decimal places. Enter a number x10-167 Submit (5 attempts remaining) Note: if your answers to (a) and (d) were graded correct, but your answer to (e) is graded incorrect, it may be due to the inaccuracies of the answers to (a) and/or (d). Double check answers to (a) and (d) to make them more accurate.

Answer 1

b We know that from Compton Scatter 8-95 mm (1-650) Hewing given that o=1620 a'a hc=h mac -0.0242 A²- ois9474109 m a=s.gyftolom 2 E s.947 Aº put the Values G scattend Photone 3.947 A – 9 = 0.0224° (1-603162) a= 5.99974934" L, Wawlength of incident photone 2 5899784-43271516m 2= 7= 0.5899 784 X 19 m 0.5899 784 nm do a E' =he Es a' I Scattend shotone Espergy of Scattend photonce (6.626113Y (3719 o-s947 X109 E'= 33.4252564318 ! 10!7J E! 3.34252 tiolog es Energy of Energy of incident Photone És he =(5-626473Y) (3418) 6.5899784109 109) = 3.369278 Xilo sta photonie E Energy incident

1.6 J momentum Incident photon's p=Ę 3.369278ti o8 mis P = 1012309 T1024 kg-m/s] 3+10 Kinetic Energy of a e - kie = DE KE; E-E! 3-369278 –3-34252)x720 KE=0.026758 tilt y
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