Question

PREVIOUS ANSWERS SERPSEWA10 17.WA.001. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER At t = 0, the instantaneous position of two pulses moving along a taut string with a speed - 28.0 m/s are as shown in the diagram below. Each unit on the hotel is 2.0 cm and each unit on the vertical axis is 5.0 cm. (The peak of pulse 2 is exactly on a hall unit of the horizontal axis.) y pulse 2 pulse 2 (a) At what location will the resultant of the two pulses have maximum amplitude? (b) At what time will the resultant of the two pulses have maximum amplitude? x What is the relationship between speed, time, and distances (c) What is the value of this maximum amplitude? 1cm

Answer 1

1 1 unit along x-axis = ? em = 5em unit along Y-anis. 1 pulses moving to each other so relative relocity = 28+28 = 56 emis Seperation beth two peak of pulses 9,5 unit. = 9.5*2 = 19.0 em Marimum amplituden will be When two peak Coincide . Time required 19.0 0-34 sec b) Time = 56 0:34 Sec 1'st harmonic on fundamental frequency fp = ILVER T is tension in string. mis mass / length. 21 h = 423 If the length is reauced to / L fundame mental frequency L'=ŽL ft' fi = 2 L! 3' I m 2.21 a bove eqn T m 173 L 2 L V 1 . 173 3 2.94 519 21 = -519 24 fi's m Velocity Vol. I so it's not depends on the length of the stroing. 346 mis mis please give a nating help me. Comment any doubt sure help. CS Scanned with CamScanner =