Homework Answers
We know that Work-done on isothermal function is given by:
dW = -P*dV
P = change in pressure during dV expansion = P0 - dP
Which gives
dW = -(P0 - dP)*dV = -P0*dV - dP*dV
Since process is reversible and dP*dV is very small, So
dW = P0*dV
Now using Integration to find total maximum work-done from V1 to V2 expansion:
Correct option is C.
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