Question

Two point charges, q₁ = 5 nC and q₂ = 4 nC, are located (3, 3) and (6, 10).

If the coordinates are measured in cm, determine the force on q₂ from q₁.

  F⃗ = ______ N, at an angle of ________ degrees with respect to the x-axis.

Answer 1

رها ره ),۶۹ (3,37

Columb's force is given as f = ka V implies that ra fis directly proportional f is to the product of a charges and inversely proportional to square of elistance between them where a Va are charges is the distance between them.

Using distance formula ce d = √ 12 - 23+ (y 7,² where x, K₂, gr, Y are co-ordinates. we get distance between q, by potting values. and a d = √58 m. we know Colombs force = kq, 9, K=9109 the values by putting we get. F = 9x10²x 5x10 x 4x109 √58 x √58 If = 3.103 X10 N or F = 3.1nN

angle between the force angl x-axis is but tan o = slope of line. o = tant (slope) Slope = m = 92-y, nothing but 10-3 6-3 x2-x, 7 3 O= lan 5" 6) = 66.809
I have drawn rough sketch in the beginning just for better understanding.

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