Question

1. A calibration curve has a least-squares equation P_e=1.61(ppm Ca²⁺). A 29.42-mL aliquot of an unknown water sample labelled hard - very hard was diluted to a total volume 297.2 mL and then analyzed by flame photometry. The emitted power was measured to be 29.9. What is the hardness of the original water sample in ppm CaCO₃?

Report answer without any decimal places. Do not enter units.

Answer 1

The objective is to calculate the hardness of the orisina water sample in ppm Given- Per 1.61 (ppm (alt) Further, 29.92 m2 hard water was diluted to 297-2mL dilution factor 297.2 - 10.) 29.42 Emitted Power of the dilukd Sample = 29.9 Pe= 1.61 (PPM C..2+) 29.95 1.61 (PPro Co2+) Ppm ca 24 29.9 1:61 Concentration of diluted hard watch = 18.570pm concentration of actual hard water = conc. Of diluted hard Watos y dilution factor 18.57 PPM 18:54 X 10.1 187