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b. To 1.200 liters of the buffer in part a, you add 3.75 mL of 2.500...

b. To 1.200 liters of the buffer in part a, you add 3.75 mL of 2.500 M barium hydroxide. What is the pH after that addition? Yes, you may use the H-H equation here. For your convenience, the buffer is 0.125 M formic acid (?a = 1.77 x 10!!) and 0.140 M sodium formate. (8 pts.)

The previous question it is referring too is a buffer of 0.125 M formic acid Ka=1.77X 10^-4 and 0.140 M sodium formate. with a PH of 3.75

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concentration of formie aid = 0.125 (M) concentration of sodium formate 0.140 (M) pH of the buffer solution 3.75 ka of formieI mol. Balottle produ 2 mol. OHO hydroxide xide in concentration, [OH-] = = 2x 7.768 2 * 10 m) 0.01558 (M) ce more Now given

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