Question

What is the coordination number (C.N.) and oxidation number (O.N.) of the transition metal in Na[Co(H2O)2(C204)2]? C.N = 4, O.N = +2 C.N = 4, O.N = +3 C.N = 6, O.N = +3 C.N = 3, O.N = +3 O CN = 6, O.N = +2

Answer 1

Answer : C.N = 4, O.N = 3

Na [co CHO), (C,Oude this can be written as [co (H₂O), (C,Oue] Here Co is the transition metal Its wordination no. is 4. Coordination no. is the no. of atoms or ions immediately surrounding a untral atom in complex or crystal. Here that there 2 water and 2 oxalate ion surrounding Cobalt. Thus its wordination no. is 4. sel In order to find the oxidation no. of the central atom, me assume that it a. Therefore, is

x + 2x(0.5 of H,0) + 2x10.5 of C20-0) z 3-1 => x + 2x0 + 2x(-2) = -1 =S x - ly = -1 il. x=4-1 =3 therefore oxidation no. of Co is 3.
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