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Fe(s) + Fe3+ (aq) + 3e The above reaction is O oxidation O neither oxidation nor...
identification half-reaction Cu(s)— Cu²+(aq) + 2€ Fe3+ (aq) + >Fe²+ (aq) oxidation reduction (2) Write a balanced equation for the overall redox reaction. Use smallest possible integer coefficients.
Half-reaction Cr3+ (aq) + 3e--Cr(s) Fe2+ (aq) + 2e - Fe(s) Fe3+ (aq) - Fe2+ (5) Sn+ (aq) + 2e - Sn2(aq) E (V) -0.74 -0.440 +0.771 +0.154 1. Calculate the standard cell potential for the voltaic cell based on the reaction below, given the table above: 35nt(s) + 2Cr (s) - 2 C (s) + 3 Sn () ANSWER: 2. Calculate the standard cell potential for the voltaic cell based on the reaction below, Riven the table above 3Feb...
Calculate the equilibrium constant, ?, for the reaction shown at 25 °C. Fe3+(aq)+B(s)+6H2O(l)⟶Fe(s)+H3BO3(s)+3H3O+(aq) The balanced reduction half‑reactions for the equation and their respective standard reduction potential values (?∘) are Fe3+(aq)+3e−⟶Fe(s) ?∘=−0.04V H3BO3(s)+3H3O+(aq)+3e−⟶B(s)+6H2O(l) ?∘=−0.8698 V K=
Half-reaction Cr3+ (aq) + 3e- → Cr(s) Fe2+ (aq) + 2e- → Fe (s) Fe3+ (aq) + e- + Fe2+ (s) Sn4+ (aq) + 2e- + Sn2+ (aq) E° (V) -0.74 -0.440 +0.771 +0.154 3Sn** (aq) +2Cr(s) → 2Cr** (aq) +3Sn²+ (aq) 3. What is the cell potential, Ecell, for the reaction above if [Sn] = 1.00 M, [Cr3+1 = 0.0200 M and [Sn2+] = 0.0100 M?
Table 20.2 Half-reaction E (V) -0.74 Cr3+ (aq) 3e --Cr (s) Fe2+(aq)+2e-Fe (s) Fe3+ (aq) 0.440 +eFe2+ (s) Sn4+ (aq) 2eSn2 (aq) +0.771 +0.154 8. Based on Table 20.2, which of the following reactions will occur spontaneously as written? A) Sn4+ (aq)+ Fe3+ (aq) Sn2+ (aq) + Fe2+ (aq) B) 3Fe (s)+2Cr3+ (aq)2Cr (s)+3F 2+ (aq) C) Sn4+ (aq)+ Fe2+ (aq) Sn2+ (aq)+ Fe (s) D) 3Sn4+ (aq)+ 2Cr (s)- 2Cr3+ (aq) + 3Sn2+ (aq) E) 3Fe2+ (aq) Fe (s)+2Fe3+...
Consider a galvanic cell that uses the half reactions: Fe3+(aq) + 3e → Fe(s) Ered=-0.04V Co2+ (aq) + 2e → Co(s) Ered - -0.28 V • 1) Calculate AGº for this reaction in kJ/mol. • 2) Calculate the equilibrium constant, K, for this reaction at 298 K • 3) What is the cell potential at 25°C when [Fe3+] - 1.09 M and [Co2+] = 0.057 M?
Table 20.2 Half-reaction E° (V) Cr3+ (aq) + 3e- → Cr(s) -0.74 Fe2+ (aq) + 2e- Fe (5) -0.440 Fe3+ (aq) + e - Fe2+ (s) +0.771 Sn4+ (aq) + 2e- Sn2+ (aq) +0.154 The standard cell potential (Eºcell) for the voltaic cell based on the reaction below is V. 35n4+ (aq) + 2Cr (s) → 2Cr3+ (aq) + 3Sn2+ (aq) A) +1.94 B) +0.89 C) +2.53 D) -0.59 E) -1.02
Calculate the cell potential for the galvanic cell in which the reaction Fe(s)+Au3+(aq)−⇀↽− Fe3+(aq)+Au(s) occurs at 25 ∘C , given that [Fe3+]=0.00150 M and [Au3+]=0.795 M . Refer to the table of standard reduction potentials. E= V
Write the balanced reduction half-reaction for the following overall reaction: 2 Fe(s) + 3 Cl(aq) → 2 Fe3+(aq) + 6 Cl(aq) Cl(aq) + 2 e → 2 Cl(aq) Fe(s) + 3 → Fe3+ (aq) Fe(s) + Cl2(aq) → FeCl3(aq) Cl(aq) → 2Cl(aq) + 2 e O 3 Cl(aq) + 2e → 2 Cl(aq)
Calculate the equilibrium constant for this reaction at 25º C, Al (s) + Fe3+ (aq) —> Al3+ (aq) + Fe (s) given the following standard reduction potentials for the two half-reactions. Fe3+ (aq) + 3 e- —> Fe (s) Eº = 0.77 V Al3+ (aq) + 3 e- —> Al (s) Eº = -1.66 V