Question

If 6.61 mL of 10.0 M NaOH is used for a reaction, calculate the number of moles of NaOH that were used. number of moles of Na
0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
If 6.61 mL of 10.0 M NaOH is used for a reaction, calculate the number of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • Calculate the grams of NaOH present in 10.0 mL of a 8.0% (m/v) NaOH solution. 8.0...

    Calculate the grams of NaOH present in 10.0 mL of a 8.0% (m/v) NaOH solution. 8.0 g 0.80 g 0.72 g 7.2 g Question 8 Which of the following solutions has a molarity of 2.0? 0.020 mole of solute in 50.0 mL of solution 3.0 moles of solute in 3.0 L of solution 0.050 mole of solute in 25.0 mL of solution 2.0 moles of solute in 500.0 mL of solution

  • 1 mol 1. Using dimensional analysis, calculate the number of moles of NaOH (nou) used in...

    1 mol 1. Using dimensional analysis, calculate the number of moles of NaOH (nou) used in reaction #1 (show your work): NaOH (mol) = mnao (9) Where non is MM NaOH (9) the number of moles NaOH, mNaOH is the mass of sodium hydroxide used, and MMNOH is the molar mass of sodium hydroxide. 2. Using the density of water (d != 1.000.), calculate the mass of the 50.0 g water used in reaction #1 using: mwater = Vwater X...

  • DATA Data Trial 1 Trial 2 Trial 3 Volume of acid (mL) 10.0 10.0 10.0 Molarity...

    DATA Data Trial 1 Trial 2 Trial 3 Volume of acid (mL) 10.0 10.0 10.0 Molarity of NaOH (M) 0.20 0.20 0.20 Start NaOH buret reading (mL) 0.00 27.02 53.61 End NaOH buret reading (mL) 27.02 53.61 80.86 Volume of NaOH used (mL) 27.02 26.59 27.25 Analysis Calculate the moles of NaOH used in each trial Trial 1 Trial 2 Trial 3 Write a balance equation for the reaction. Calculate the moles of HCl used in each trial Trial 1...

  • A 10.0 mL volume of 0.250 M HNO3 is titrated with 0.150 M NaOH. Calculate the...

    A 10.0 mL volume of 0.250 M HNO3 is titrated with 0.150 M NaOH. Calculate the pH of the solution after addition of 15.0 mL of the NaOH solution.

  • Exact molarity of 1M NaOH used is 1.083M, the volume of NaOH used is 10.0mL, the...

    Exact molarity of 1M NaOH used is 1.083M, the volume of NaOH used is 10.0mL, the final volume of stock NaOH is 100.00mL, and the molarity of stock NaOH solution is 0.1083M. KHP had a molar mass of 204.2 g/mole. acid base titration, part A B. Titration of KHP 1. 2. 3. Mass of KHP Initial buret reading Final buret reading Trial 1 Trial 2 0.30T usly & 0.00ml D.DD_ml 15.3 L 142 ml t is 1/0 ml _mol mol...

  • If 50.0 mL of 0.88 M H2O2 and 10.0 mL of 0.50 M Fe(NO3)3 were combined...

    If 50.0 mL of 0.88 M H2O2 and 10.0 mL of 0.50 M Fe(NO3)3 were combined and a temperature change of -6.61°C was observed, The specific heat of water is 4.18 J/(g * ∘C) Calculate the heat of reaction (in kilojoules). Record your answer with the proper significant figures and include the correct sign if needed.

  • 9) 19.63 mL of 0.100 M NaOH is required to neutralize 2.00 mL of a solution...

    9) 19.63 mL of 0.100 M NaOH is required to neutralize 2.00 mL of a solution containing acetic acid according to the following reaction:HC2H3O2(aq) + NaOH(aq) → NaC2H;O2(aq) + H2O(1). How many moles of NaOH were used in this titration? Report the correct number of significant figures, and report the units. 10) 19.63 mL of 0.100 M NaOH is required to neutralize 2.00 mL of a solution containing acetic acid according to the following reaction: HC2H302(aq) + NaOH(aq) → NaC2H:02(aq)...

  • hort Answer. Show all work! No credit will be given when only answers are given. 8. Based on the reaction given below, which we did in Exp 7 -Ka of a weak acid. 20.0 mL of 0.50 M HCaHsO2 and 10.0...

    hort Answer. Show all work! No credit will be given when only answers are given. 8. Based on the reaction given below, which we did in Exp 7 -Ka of a weak acid. 20.0 mL of 0.50 M HCaHsO2 and 10.0 mL of 0.50 M NaOH were mixed together in the reaction shown below, Fill in the rest of the data table. (12 points) Vol.0.50 M (mL) 20.0 mL Vol. 0.50 M 10 (mL) 10.0 mL moles HC2HsO2 initial moles...

  • 20. A 0.20 M NaOH Intention was used to literate the acetic acid in 10.0 mL...

    20. A 0.20 M NaOH Intention was used to literate the acetic acid in 10.0 mL of an unknown Salesian The total haline of NaOH alertian used Completely neutralize the acesic alld in the solution was up to Calcubre the maksity of acetic acid in the linkown Soladian. 30.20 mL

  • 1.If 23 ml of 2.0 M NaOH was required to neutralize 10.0 ml of HCl, what...

    1.If 23 ml of 2.0 M NaOH was required to neutralize 10.0 ml of HCl, what is the molarity of the HCl? 2.What volume (in L) of a 2.08 M NaOH solution is required to neutralize 0.53 mol of HCl? *Remember to report your answer using the proper significant digits. 4.A student has finished the titration of a sample of HBr of unknown concentration with 0.2 M NaOH. The student notices small drops of unreacted NaOH were left on the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT