Question

Which of the following will result in an output of: 8 def pass_it(x, y): z = x**y return(z) num1 = 2 num2 = 3 answer = pass_it(numi, num2) print(answer) def pass_it(x, y): z = y*** return(z) num1 = 2 num2 = 3 answer = pass it(numl, num2) print(answer)

Answer 1

Answer() Option A will produce result 8

Option(A)

def pass_it(x,y)
z = x**y // assume ** is exponentiation operator // z = 2³ = 8
return(z)

num1=2
num2=3
answer= pass_it(num1,num2)
print(answer)

................................................................

Option(B)

def pass_it(x,y)
z = y**x;   // assume ** is exponentiation operator // z = 3²   = 9
return(z)

num1=2
num2=3
answer= pass_it(num1,num2)
print(answer)

.................................................................

Option(C)

def pass_it(x,y)
z = 2*3 // it is normal multiplication // z = 2*3 = 6
return(z)

num1=2
num2=3
answer= pass_it(num1,num2)
print(answer)

.............................................................................   

Option(D)

def pass_it(x,y)
z = x^y   // it is XOR operation    // z = 2 XOR  3 = 1   // (10)₂XOR (11)₂ = (01)₂
return(z)

num1=2
num2=3
answer= pass_it(num1,num2)
print(answer)

..................................................................................