Question

Please code in C++! I'm not too sure what the blue box session is but I included it. Please help if you can

8.2: Lottery Winners A lottery ticket buyer purchases 10 tickets a week, always playing the same 10 5- digit "lucky" combinations. Write a program that initializes an array or a vector with these numbers and then lets the player enter this week's winning 5- digit number. The program should perform a linear search through the list of the player's numbers and report whether or not one of the tickets is a winner this week. Here are the numbers: 13579 26791 26792 33445 55555 62483 77777 79422 85647 93121 SAMPLE RUN #1: ./ETest Interactive Session (Hide Invisibles) Highlight: None Show Highlighted Only Enter this week's-5-digit winning lottery. number:-52 You did not win this week.

Answer 1

Answer:

#include <iostream>
using namespace std;
int main()
{
int lottory[10]; //decalring array
int winner,count=0; //declaring variables
cout<< "Enter 5 digit lottory numbers >>>";
for(int i=0;i<10;i++) //loop to taku user input
{
cin >> lottory[i]; //taking user input
}
cout << "Enter winner lottory number >>>";
cin >> winner; //taking user input
for(int i=0;i<10;i++) //loop to search lineraly
{
if(lottory[i]==winner) //linear search
{
cout << "You won the lottory"; // printing output
count++; //to check the case of not found
}
}
if(count==0) //case if not found the winner lottory card in your 10 cards
{
cout << "You didn't won the lottory"; //printing output
}
return 0;
}

#include <iostream> 2 using namespace std; 3 int main() 4-{ int lottory[10]; //decalring array int winner,count=0; //declaring variables cout<< "Enter 5 digit lottory numbers >>>"; for(int i=0;i<10; i++) //loop to taku user input 9 { 10 cin >> lottory[i]; //taking user input } 12 cout << "Enter winner lottory number >>>"; cin >> winner; //taking user input 14 for(int i=0;i<10; i++) // Loop to search lineraly 15 { 16 if(lottory[i]==winner) //Linear search 17 - { 18 cout << "You won the lottory"; // printing output 19 count++; //to check the case of not found 20 } 22 if(count==0) // case if not found the winner Lottory card in your 10 cards 23. { 24 cout << "You didn't won the lottory"; //printing output 25 26 return 0; 27 } سہا 21 }

output:

Enter 5 digit lottory numbers >>>12345 12222 11111 34567 45678 56789 13456 14567 15678 16789 Enter winner lottory number >>>15678 You won the lottory

Enter 5 digit lottory numbers >>>12345 13456 14567 15678 16789 23456 24567 25678 26789 34567 Enter winner lottory number >>>18675 You didn't won the lottory

Note: Blue box session is just sample output to verify the code like the output I uploaded in this answer.Its just one test case to understand the question better.