Question

Question 13 0.5 points Save Answer Shown in the figure below is a solid cylinder. The x-axis is along the longitudinal direction. The angle is measured with respect to the x-axis, positive if counterclockwise, i.e. towards the y-axis as shown below, and negative if clockwise. 01 and 02, with 01207 are the principal stresses, and Tmax is maximum shear stress. LO Fractute surface Normal to Fracture surface Suppose that the cylinder is subjected to a uniform tensile stress of sooo psi in the longitudinal direction. The orientation () for O2 is: O 30° 90" 0 450

Answer 1

13) 90 degrees

Because principal stress both maximum and minimum life at an angle of 90 degrees.

14)$\sigma_x$

Because for unidirectional stress, in Mohrs circle maximum value $\sigma_1=\sigma_x$ and $\sigma_2=0$

15) 45 degrees

The orientation of $\tau_{max}$ is 45 degree with normal principal stress.