Question

Question 6 (10 pts) Steam distillation can be run more efficiently in some cases using super-heated steam at 1 atm pressure rather than boiling water. By increasing the temperature of the steam beyond the boiling point of water in a controlled fashion, the oil may still be protected from degradation while increasing its contribution to the vapor composition, making the process more efficient. At 150 °C, linalyl acetate exerts a vapor pressure of 93 torr. If a steam still were run using steam heated to this temperature in place of boiling water, how much water must co-distill to collect 1.0 grams of linalyl acetate? Include your calculations.

Answer 1

From handbook at T = 150°C

Vapor pressure of water(PA) = 3587.2 torr

Vapor pressure of linalyl acetate(Pb) = 93 torr

M.W of water = 18.02 g/mol

M.W of linalyl acetate = 196.29 g/mol

For steam distillation

WA РА (МА PB MB Wь

Mass of linalyl acetate distilled = 1 g

$\frac{W_{A}}{1}= \frac{3587.2}{93}\left ( \frac{18.02}{196.29} \right )$

WA = 3.54102 g

3.54102 g of water is to be distilled to have 1 g linalyl acetate

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