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Question 21
Solve the systems in Exercises 19-24 with the elimination method. Check your answers by substituting them back in. (Answers a
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Answer #1

19 1 23+1 =s M hr 22. (1) eqw (11 2 x cano 4 -?) ? 2 +1°. 4 +6 д - 8 = - 8 c) - 1 ха e 1 СЛК 2 +3} = 3 2x2 + 3x1 (ок) S (20 -37-17 = 27 4 x - sy: 23 Quba xp 3х си 0 12 - 28 — 287 2 (o 8 12 - 15 69 — 137 39 -) - - 3 х- 2 check L7 L- хя. (8-) XL-exe 6224 К-12 12 2 3 egn 3х +37 = 2. eque equo 1) + 4x equ cx - 2 -11 - 9 +12y 9 | 2х + = 8 + + т 11 17 Х 1 ya = - Смк 3х + 3 = 2 3

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