Question

2. [-13 Points) DETAILS LARCOLALG10 5.3.079. The relationship between the number of decibels 3 and the intensity of a sound I (in watts per square meter) is B = 10 log = 10 100 10=12) Use the properties of logarithms to write the formula in simpler form. B = Determine the number of decibels of a sound with an intensity of 10 ** watt per square meter. dB Show My Work Aqua Mihatsteps of reasoning did you use? Your work counts towards your score You can submit show my work an unlimited number of times

Answer 1

The relation between the number of decibels ß and the intensity of a sound I (given) now B = lolog ( ) Ingawthan properties log (96) laga-logo we know the So, B = to log ( 12 ) = lo {log 1 - log 1812 - Ho [log I - (-12 108 10 to (rag It izlagio

B = [leget 120 2.2008] when base é' lo log 1 + 276.3 110 / log I + 27.63 then logo 10 when base 'lo lo [ log It 12 2] [ log 2 + 12 12] Isolog It 120

intensity '1' of when the sound is 10 Lu m2 - B lolog / lolog [ ] 1812 lo tog, 10 To 10 do when base 'e' lot 2.3025=/23.025 dB Given: - let the dimension of rectangular track breadth 'bi length 'l and k L Perimeter of rectangle is 6.4km = 2(1+b) 32= d+b Area - l b = 255 km2 = be 255 - (2) l put b'= 255 into =) e eqC1) 32= l +255 l 2+255=320 le - 32 l + 255=0 -(3) wsing quadratic formula - e = -btj 62-4ac 2 a -) 32 + 1 (32)2 - 4 X 18255 32 2 5 waya 1020 2 cro 2

32 + 5 zu 32 + 256 16156 2 2 16+56, 16-ro こ 18.44 km 13.55km Pb 32 = lfb 32 = 18, 44th breadth -) 32 - 18.uyr b = 13.56 km 32 - bt 13.55 . 32-13.55. 18.45km 1 1,8418.498 m, 13.50 13.56 km) 13.58 km, 18.48 km