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For the beam shown, calculate the Reactions at A and B, and then draw the Shear and Bending Moment diagrams. Consider the loa

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The answer is shwon in the below hamdwritten notes :

P = 29 kNike B An 40KN 40kn X f 6.6m 1.8m o.im Answer- P=2akulm IT sopparrt reactions Bay taking moments about a By * i SMA=0

SF @ just be faré ce 66-1 KN shear Force SE @ A - 6601 ko SF @ just after c = 66 1-40 = 26.1 kN SF @ just before D=66-1-40 -

BM @ B- 0 kNm. Bending moment :- BM @ A=0 kom. BM @ c = (661x06) = 39.66 kNm BM @ D= (66. 1x 2) - (40X 1-8)– (29x1-8X18 ) = 3

shear Forcé & Bending moment diagrams: - A B -0-6m- 2.40kn 1.8m 0-6m 140KN Ay By 66.1K 66-1 KN - tve 26.1 kN K 18-2 ko.am 2

Bending . The Maximom moment occurs at where the shear Force & zoro From similar triangles 26.1 km log-d. k 1.8-2 a 26.1kJ x

Maximum left support Bending moment occuses at 1.5m from (66.1X1-5) – (404019) - (29x0-9x 039) BM max = 51-405 kNm

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