Question

Question 3 30 pts 212 412 w 12 -90° A 4 -j512 32 Find the Thevenin equivalent of the circuit with respect to Zų. Express the answer in terms of the Thevenin voltage Vr), short-circuit current (isc), and Thevenin impedance (Zr). Round answer to 2 decimal places, add trailing O's as needed. Vr = ov 2 A ZT= 12

Answer 1

37. 42 22 А. N L 1<-98 -sir Thevenin Equivalent impedence (zu) across A B can be vind out by open circuit current source 2r ir А. Ju ZT -sje- As no current can be passed through 42 because open Circuited so 42 resistor can be removed -sial B 22 m :-)52 2-т 뭐 so, 22 resistor in seriee with capacitor so, Zy=(2-sj je ZT = 5.38 %-6802 r

isc for finding have to short AB and passing Current ise 2 R. 42 -si 14-9000 isc B Now, by Current division rule Isc-612-909)65;) 2-5 5.928 <-111.89 isca.928 <117.8 Now, no so V through ae B we zind thevenin voltage across AB as 4r 22 AS A-B is open + current pars 12-990 -53 resistance. Mecury voltage across Capacitor is as v V voltage across Capacelor S cime (12-90°)(-53) = 5(-180 Capacitor = AS voltage across Vp = 5 4-120lv
please upvote if you like the solution