Question

Which of the following code will print all odd numbers between 3 and 11, each number separated by a space as shown below 35 7 9 11 for i in range(3, 11, 1): if 1%2 ID: print(i, end = " for i in range(3, 10, 2): print(i, end = for i in range, 11, 2): if 152 == 0: print(i, end = "") for i in range 12, 1): print(i, end = "")

python programming

Answer 1

Question:
Which of the following code will print odd numbers between 3 and 11, each number separated by a space as shown below:
3 5 7 9 11
Ans:
for i in range(3,12,2):
print(i,end=" ")

Now check with the options, what each loop prints:
1. In the first loop
for i in range(3,11,1):
if i%2 != 0:
print(i,end=" ")
This will print the values: 3 5 7 9 but not 11, because 11 is not included, only up to 10, is included. so we are incrementing it by 1 and the if condition checks if the number is not divisible by 2. If we place 12 in place of 11, then this loop will print the exact same output needed.

2. In the second loop
for i in range(3,10,2):
print(i,end=" ")
This will print the values 3 5 7 9. Here, we are starting from 3, and ending up to 10(10 is excluded) and being incremented by 2 which prints even numbers obviously within 10. we need 11 too. If we change to 12, in place of 10 then this loop will print the exact same output needed.

3. In the third loop,
for i in range(3,11,2):
if i%2 == 0:
print(i,end=" ")
This will not print anything, the thing is we are using a for loop to fetch all the odd numbers and inside the loop, we are checking for even case and then printing if the number is even. so this will never print anything.

4. In the fourth loop,
for i in range(3,12,2):
print(i,end=" ")
This will print the exact same output, which is 3 5 7 9 11 since we are fetching only the odd numbers with an increment of 2 starting from 3 to 12(12 is excluded anyway)

Please check the compiled program and its output for your reference:

main.py 1 print("Loop 1") 2 - for i in range(3,11,1): 3 if i%2 != 0: 4 print(i,end=" ") 5 6 print("\n\nLoop 2") 7 for i in range(3,10,2): 8 print(i,end=" ") 9 10 print("\n\nLoop 3") 11 for i in range(3,11,2): 12 if i%2 == 0: 13 print(i,end=" ") 14 15 print("\nLoop 4") 16- for i in range (3,12,2): 17 print(i,end=" ")

Output:

input Loop 1 3 5 7 9 Loop 2 3 5 7 9 Loop 3 Loop 4 3 5 7 9 11 ... Program finished with exit code 0 Press ENTER to exit console. I

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