Question

Find Is, Ic , Vce and the region of operation, 20012 IM 3v 63200

Answer 1

200m 3V TM M giren ß = 200. с B Lets take this is a silicon transistor. so it has VIBE = 0.tv, - Lets assume this Dpo transistor is in active region for time being. writing Kul equation along peeth gures 3+ 200 IE & 1 (IB) +0.450 - I= IC tab and Te = 8 PB So Te = 200 RB IDE 2012 in eq gores substituting ea & &B= 2.211 HA I c = 0.442 MA PE=0.444 MA. from the given diagram: VE=OV Vo = 0.71 (Vee - NB - VE = 0:47) to find Ve=) -34 200 IB & Vc co. Vc= 2.9118 Vo > VB for non transistor, this region transistor is active

VCE - Vc - VE 2.911 - 0 VCE 2.9117 Region of operation → Active region final results Ip= 2.211 HA Ic= 0.442 MA 2e = 0.444 mA VCE - 2.9118 region of operation Active region.