Question

2. [-/10 Points] DETAILS DEVORESTAT9 9.E.046. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER As part of a larger project to study

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Since the 16 observations belongs to same lumber specimen of 1 min and 4 weeks. So, we use Paired t - test.

Let X = 1 Min

Y = 4 Weeks

X Y d = X - Y (d - \bar{d}) (P-P)
10420 9180 1240 -1365.63 1864931.6406
16620 13250 3370 3370 11356900.0000
17100 14720 2380 2380 5664400.0000
15480 12740 2740 2740 7507600.0000
12920 10120 2800 2800 7840000.0000
17260 14570 2690 2690 7236100.0000
13400 11220 2180 2180 4752400.0000
13900 11100 2800 2800 7840000.0000
13630 11420 2210 2210 4884100.0000
13280 10930 2350 2350 5522500.0000
14370 12110 2260 2260 5107600.0000
11700 8650 3050 3050 9302500.0000
15470 12590 2880 2880 8294400.0000
17840 15090 2750 2750 7562500.0000
14010 10550 3460 3460 11971600.0000
14760 12230 2530 2530 6400900.0000
TOTAL 41690 113108431.6406
MEAN 2605.6250

\bar{d} = 2605.6250

\Sigma (d - \bar{d})^{2} = 113108431.6406

S^{2} = \frac{1}{n-1}*\Sigma (d - \bar{d})^{2} = \frac{1}{16-1}*113108431.6406

\Rightarrow S^{2} = 7540562.109

Therefore

S.E(d) = \sqrt{\frac{S^{2}}{n}} = \sqrt{\frac{ 7540562.109}{16}} = \sqrt{471285.1318} = 686.5021

Since Confidence Interva = 95%. So,the level of significance = \alpha = 5% = 0.05

t_{cri} = t_{(n-1). \alpha } = t_{(16-1),5\%} = t_{15,0.05} = 2.1314

EXCEL COMMAND FOR t_{cri} is

=T.INV.2T(0.05,15)

Margin Error:

E_{\alpha } = S.E(d)*t_{cri}

E_{\alpha } =686.5021*2.1314=1463.2106

Therefore the 95% Confidence Interval of \mu _{d} is

\bar{d} - E_{\alpha } \leq \mu _{d} \leq \bar{d} + E_{\alpha }

\Rightarrow 2605.6250 - 1463.2106 \leq \mu _{d} \leq 2605.6250 + 1463.2106

\Rightarrow 1142.4144 \leq \mu _{d} \leq 4068.8356

\Rightarrow 1142.41 \leq \mu _{d} \leq 4068.84

The Upper Confidence Bound for the true average difference between 1 Min modulus and 4 Week modulus is

4068.84

**********************************

Therefore we are 95% Confident that the true mean difference between 1 Min modulus and 4 Week modulus is atmost the Upper bound.

OPTION (C)

************************

NOTE: We can also extract the t_{cri} value from the tabulated value which is posted below.

t 999 t Table cum. prob. one-tail two-tails df t.50 0.50 1.00 0.25 0.50 7.80 0.20 0.40 1.8 0.15 0.30 t90 0.10 0.20 4.95 0.05

Add a comment
Know the answer?
Add Answer to:
2. [-/10 Points] DETAILS DEVORESTAT9 9.E.046. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER As part of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • As part of a larger project to study the behavior of stressed-skin panels, a structural component...

    As part of a larger project to study the behavior of stressed-skin panels, a structural component being used extensively in North America, an article reported on various mechanical properties of Scotch pine lumber specimens. Data on the modulus of elasticity (MPa) obtained 1 minute after loading in a certain configuration and 4 weeks after loading for the same lumber specimens is presented here. Observation 1 min 10,460 16,620 17,400 15,480 12,930 17,260 13,400 13,900 13,630 13,290 14,370 11,700 15,470 17,840...

  • 1. [-15 Points] DETAILS DEVORESTAT9 9.E.003.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Pilates is a...

    1. [-15 Points] DETAILS DEVORESTAT9 9.E.003.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Pilates is a popular set of exercises for the treatment of individuals with lower back pain. The method has six basic principles: centering, concentration, control, precision, flow, and breathing. An article reported on an experiment involving 88 subjects with nonspecific low back pain. The participants were randomly divided into two groups of equal size. The first group received just educational materials, whereas the second group participated in...

  • 3. [-16.5 Points] DETAILS DEVORESTAT9 12.E.015. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Values of modulus...

    3. [-16.5 Points] DETAILS DEVORESTAT9 12.E.015. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Values of modulus of elasticity (MOE, the ratio of stress, i.e., force per unit area, to strain, i.e., deformation per unit length, in GPa) and flexural strength (a measure of the ability to resist failure in bending, in MPa) were determined for a sample of concrete beams of a certain type, resulting in the following data (read from a graph in the article "Effects of Aggregates and...

  • 2. [-/10 Points] DETAILS DEVORESTAT9 10.E.003. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The lumen output...

    2. [-/10 Points] DETAILS DEVORESTAT9 10.E.003. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The lumen output was determined for each of I = 3 different brands of lightbulbs having the same wattage, with J = 7 bulbs of each brand tested. The sums of squares were computed as SSE = 4776.4 and SST = 598.4. State the hypotheses of interest (including word definitions of parameters). u; = sample average lumen output for brand i bulbs Ho: M1 = ll2 =...

  • MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER 2. [-12 Points) DETAILS DIEZSTAT3 5.E.030. Consider the diamond...

    MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER 2. [-12 Points) DETAILS DIEZSTAT3 5.E.030. Consider the diamond prices (standardized by weight) for diamonds with weights 0.99 carat and 1 carat. See the table for summary statistics, and then construct a 95% confidence interva for the average difference between the standardized prices of 0.99 and 1 carat diamonds. You may assume the conditions for inference are met. (Round your answers to two decimal places.) 0.99 carat 1 carat Mean $43.53 $56.81 SD...

  • -/10 POINTS DEVORESTAT9 7.E.015. MY NOTES ASK YOUR TEACHER Determine the confidence level for each of...

    -/10 POINTS DEVORESTAT9 7.E.015. MY NOTES ASK YOUR TEACHER Determine the confidence level for each of the following large-sample one-sided confidence bounds. (Round your answers to the nearest whole number.) (a) Upper bound: x + 1.04s/n % (b) Lower bound: - 2.33s/n (c) Upper bound: x + 0.52s/ You may need to use the appropriate table in the Appendix of Tables to answer this question. Need Help? Read It Watch It Talk to a Tutor -/10 POINTS DEVORESTAT9 7.E.503.XP. MY...

  • 2. + -/6 points DevoreStat9 5.E.064. My Notes + Ask Your Teacher Suppose your waiting time...

    2. + -/6 points DevoreStat9 5.E.064. My Notes + Ask Your Teacher Suppose your waiting time for a bus in the morning is uniformly distributed on [0, 12), whereas waiting time in the evening is uniformly distributed on [0, 16] independent of morning waiting time. (a) If you take the bus each morning and evening for a week, what is your total expected waiting time? (Assume a week includes only Monday through Friday.) (Hint: Define rv's X, ..., X10 and...

  • 3. [3/4 Points] DETAILS PREVIOUS ANSWERS PODSTAT5 11.E.010. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Do...

    3. [3/4 Points] DETAILS PREVIOUS ANSWERS PODSTAT5 11.E.010. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Do male college students spend more time than female college students using a computer? This was one of the questions investigated by the authors of an article. Each student in a random sample of 46 male students at a university in England and each student in a random sample of 38 female students from the same university kept a diary of how he or she...

  • ====================================================================== 1. (4.64/7 Points] DETAILS PREVIOUS ANSWERS DEVORESTAT9 12.E.011.5. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER...

    ====================================================================== 1. (4.64/7 Points] DETAILS PREVIOUS ANSWERS DEVORESTAT9 12.E.011.5. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Suppose that in a certain chemical process the reaction time y (hr) is related to the temperature (°F) in the chamber in which the reaction takes place according to the simple linear regression model with equation y = 4.10 - 0.01x and c = 0.07. USE SALT (a) What is the expected change in reaction time for a 1°F increase in temperature? For a...

  • 5. [-/1 Points] DETAILS MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Due to a weak connection,...

    5. [-/1 Points] DETAILS MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Due to a weak connection, there is a break in the circuit (shown below) between points a and b. If R1 = 3.73 12, R2 = 1.892, and R3 = 14.712, and the two batteries &, and have voltages of 20.0 V and 6.50 V respectively, find the potential difference Vab. Be sure to include the sign of the potential difference. Vab = Vb - Va= V "+ R1...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT