A researcher wanted to know if one's race had an impact on the number of interactions with police over the span of a month. The following is a random sample of interactions with police grouped by race. Test the null hypothesis that the number of interactions with police does not vary by race.----ANOVA METHOD----
| White | Black | Asian | Native American or Alaska Native | Native Hawaiian or other Pacific Islander |
| 1 | 7 | 3 | 8 | 7 |
| 6 | 7 | 4 | 4 | 5 |
| 2 | 9 | 3 | 9 | 6 |
| 1 | 4 | 1 | 3 | 7 |
| 0 | 8 | 2 | 1 | 1 |
We have to perform one way anova on the five groups.
Null Hypothesis: the number of interactions with police DOES NOT vary by race.
Alternate Hypothesis: the number of interactions with police DOES vary by race.
We will choose 95% confidence level for the ANOVA.
We will perform anova on ti 84.
Step 1: input the data into list L1 L2 L3 L4 and L5.
To do this Press [Stat] and then press Edit.



Step 2: To perform the one-way ANOVA. Press [Stat] and then scroll over to TESTS. Then scroll down to ANOVA and press [Enter].

Enter the lists where the data is stored separated by commas, then add a closing parenthesis ) and then press [Enter]

Note: To make L1 appear, press 2nd and then press 1. Similar for other list by looking at appropriate number aftee pressing 2nd.
Step 3: Interpret the results.


The F-statistic for the test is 3.74 and the corresponding p-vaule is 0.02. Since this
significance value is 0.02 (i.e., p = .02), which is below 0.05. and, therefore, we reject the null hypothesis.
there is a statistically significant difference in the mean number of interactions with the police for different race.
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A researcher wanted to know if one's race had an impact on the number of interactions...
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