Question

Answer A (i), (ii), (iii), B (i), (ii), (iii)

Score: 0 of 1 pt 14 of 20 (20 complete) X 6.3.107 "S & st The table below shows a relative-frequency distribution for the heights of female students at a midwestern college. The heights are approximately normally distributed with mean 64.5 inches and standard deviation 1.9 inches. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. Use a normal distribu approximate the perc heights within any sp (i) obtain the exact pe normal distribution to (iii) compare your ans a. The percentage off between 62 and 63 inc (1) The actual percentag between 62 and 63 inch (Type an integer or a de Frequency Height (inches) 60-61 61-62 6263 63-64 64 65 65 66 66 67 67 68 68 69 2 8 24 63 91 61 28 8 3 288 Relative frequency 0.0069 0.0278 0.0833 0.2188 0.3160 0.2118 0.0972 0.0278 0.0104 1.0000

Answer 1

Answer:-

@ [)| The actual percentage ots female Students with height between 62 and 63 inches is 244288 xloo ole 0.08.33 X 100 Y, = 8.33.1 C u = 64.5 inches = 1.9 inches X ~ N(64.5, 1.g) Normal desteibution approximates the percentage of female students with heignt between 62 and 63 inches to be Pl62<x<63) =PL62-64.542363-64.5 lig T-g -2.5 K2x -1.5 てま =pl -PL-1316<2<0.789 =plz <-0.789) - Plz<-1.316 0.12097 - 12.0970), -12.097/ -12:00 13. 12 de place)

A MAMA 62-664.5

(iii) The approximate percentage.us greater than the actual percentage. be 10 The actual percentage of female students with height between Grand 68 inches is 65.27lo, g1+61 +28+8 288 188 788 => 0.6527 >> 65,27% L. lii) M = 64.5 inches olig inches X N64.5, 1.9 therefore,

the noumal approximation the percentage of female students with height between 64 and 68 inches is P(648X (68) P/ 64-64-5/2268-6415 Tog Tog P 3.5 -0.5 log PL0_26316<2<1.8421) PL-0.26316<270) + PLO<2<1.8421) 0.10379 +0.46727 1 =0.57.106 E 57,106 / = 57. 11 olo rounded to 2 d. place ül the approximate percentage is less than the actual percentage : 5 Less then

o ( प 4564.568