
1. Find the Laplace transform of the function f(t) = 1 + 2t + 3e-3t - 5 sin(4t). Solution: 2. Find the inverse Laplace transform of F(s) = 7+ (8 + 4)(18 - 3s) (s - 3)(s – 1)(s + 4)" Solution:
QUESTION 12 Apply Laplace Inverse to find f(t): s +7 F(s) = 5(52 + 4s +3) Choose the correct answer: L-'[F(s)] = f() 1) f(1) = 4t’e-31 - 3e-+ + 7t 2) f(t) = 5t? - 3e-4 3) f(0) =2-31 - 3e-- + 4) f() = 6e-6 - e-31 +} QUESTION 13 Solve the ODE: 2 2 + 3ź - 2z = te-2 z(0) = 0 & ż(0) = -2 Choose the correct answer: 1) z(t) = -0.768 0.5t -...
Find L 2s+4 s(s2+4) 5 -3t (write 5/6 by 5 e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).
2 + 3s +2 (2s + 9)e-38 20. If F(s) = ? (S-2)(2+4)52+45 + 13 then L-'[F(s) = 2e2+ i sin 2x, OSI<3 (a) f(x) = { 2e2(-3) cos 3.- 3) + 2(1-3) sin 3(2x - 3), 1 3 2e22 + 3 cos 21, 0<x<3 2e2+ + 3 cos 2x + 2e-22 cos 3.0 + e -2- sin 3r, r>3 2e2+ + 2 sin 21, 05x<3 2e2+ sin 2r +2e-2(-3) cos 3(x - 3) + e -2(2-3) sin 3(-3), 1...
find L^-1 {2s+4 / s(s^2+4)}
2s+4 Find L s(s2+4) 5 -30 (write 576 by 6 e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t).
Find the inverse Laplace transform of the function F(s) s +1 $2 - 8s + 20 * uz(t)e(4t-12) (cos(2t – 6) + 2.5 sin(2t – 6)) OF U3(t)e4t (cos(2t – 3) + 0.5 sin(2t – 3)) OC e(4t-12) (cos(2t – 3) + sin(2t – 3)) OD uz(t) (cos(2t – 6) + sin(2t – 6)) ОЕ uz(t) (e4t – 5t)
Select the correct statement. 3e-8 52 + 9 *} sin(3t) *e! O N {}={2- t <3 3 t > 3 O None of the other options о {*} = 6(e – 2)51 OL-{L {** f(t)}} = f(") (t) Select the correct statement. of{e * sin(2) +e*t} - 2+2+5 8 (-3) None of the other options O L {eztult - 3)} = e-3 L {e2(t-"}} w O (t + 1)2 5 (t-1) 5 x{05e-1) + at -1)}- di (-4e")+eos ${sin(t –...
QUESTION 5 Find L 2s+4 s(s2+4) 5 (write 5/6 by 6' e^{-3t} by e -30 and sin(2t) or cos(3t) by sin(2t) or cos(3t)).
find L^-1 {4s/s^2 + 2s -3}
4s Find L s2 + 25 - 3 5 -3t (write 5/6 by 6' , e^{-3t} bye and sin(2t) or cos(3t) by sin(2t) or cos(3t)).
Find L^-1 {2s+7/ s^2 + 4s + 13}
-1 Find L 2s+7 S2 +45 +13 (write 5/6 by 5 6 e{-3t} by e -3t and sin(2t) or cos(3t) by sin(2t) or cos(3t)).