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a) We will check this by finding the confidence interval.
n = 100, x = 44
p̅ = x/n = 0.44
95% Confidence interval :
At α = 0.05, two tailed critical value, z_c = NORM.S.INV(0.05/2) = 1.960
Lower Bound = p̄ - z_c*√( p̄ *(1- p̄ )/n) = 0.44 - 1.96 *√(0.44*0.56/100) = 0.343
Upper Bound = p̄ + z_c*√( p̄ *(1- p̄ )/n) = 0.44 + 1.96 *√(0.44*0.56/100) = 0.537
0.343 < p < 0.537
As the value 0.33 is not in the interval so we will reject 0.33
As the value 0.34 is in the interval so we will not reject 0.34
The value 0.53 is included in the so we will not reject 0.53
As the value 0.54 is not in the interval so we will reject 0.54
Do not reject the null hypothesis for the values of p0 between 0.34 and 0.53, inclusively.
Do Not Solve. please delete A blind taste test is conducted to determine which of two...
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A blind taste test is conducted to determine which of two colas, Brand A or Brand B, individuals prefer. Individuals are randomly asked to drink one of the two types of cola first, followed by the other cola, and then asked to disclose the drink they prefer. Results of the taste test indicate that 48 of 100 individuals prefer Brand A. Complete parts a through c. Do not reject the null hypothesis for the values of po between 0.39...
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