
Hit like please.
The diameter measurements of an armored electric cable, taken at n=25 points along the cable, gave...
Question 20 4 pt The diameter measurements of an armored electric cable, taken at n=25 points along the cable, gave a sample standard deviation s= 0.3 cm. Compute a 95% confidence interval for the variance o? of diameter of these cables. Assume that the population distribution is normal. 0 (0.0593, 0.1560) 0 (0.0548, 0.1742) O (-1.0465, 1.0465) (0.0531, 0.1478)
(10 pts) 8. Ina random sample, the diameter measurements of an armored electric cable, taken at n-25 points along the cable, gave a sample mean - 2.1 cm. Assume the standard deviation a- 0,3 cm. Estimate the true mean diameter u of the cable by a 808 confidence interval.
Please be as detailed as possible and provide solution without
using to software
Problem 3 sample of 15 measurements was taken and the sample mean was 3.7867 and the sample variance was 0.94265. Assuming that the measurements represent a random sample from a normal population, (24 points): Measurements were recorded for the aeriation time of a process. A random a) Construct a 95% confidence interval for the mean drying time Construct a 95% prediction interval for the drying time for...
A sample of 25 observations is taken from a normal distribution with a population variance of 9. The sample mean is 5. The 95 percent confidence interval for the population mean is from A 3.82 B 6.18 C 3.76 D 6.24
Pg 417 6.47 For a hypothesis test H0: p = 0.3 Ha: p < 0.3 a random sample of size n 200 is taken and the sample proportion p = 0.21 (a) Determine whether it is appropriate to use the normal distribution to estimate the p-value. (b) If it is appropriate to use a normal distribution, complete the test for a significance level of 5% Pg 418 6.55 Home Field in Baseball 2009 There were 2430 Major League Baseball games played in 2009, and the home team won the...
Find the critical values x?and XR for the given confidence level c and sample size n. C=0.8, n=30 xL= (Round to three decimal places as needed.) Find the critical values x and x for the given confidence level c and sample size n. c=0.9, n=21 x?L= (Round to three decimal places as needed.) Use technology to construct the confidence intervals for the population variance o2 and the population standard deviation o. Assume the sample is taken from a normally distributed...
(2 Points) A random sample of size n = 25 is taken from a population with mean u = 530 and standard deviation o = 100. Then the sampling distribution of the sample mean X has normal distribution with mean 530 and standard deviation 20 has normal distribution with mean 530 and standard deviation 100 has normal distribution with mean 530 and standard deviation 2 has normal distribution with mean 530 and standard deviation 4
11. A random sample of 25 statistics examinations was taken. The average score in the sample was 76 with a variance of 144. Assuming the scores are normally distributed, the 99% confidence interval for the population average examination score is 70.02 to 81.98 6. 69.82 to 82.18 70.06 to 81.94 d. 69.48 to 82.52 2. c. 12. It is known that the population variance equals 484. With a 0.95 probability, the sample size that needs to be taken to estimate...
1. A bearing used in an automotive application is supposed to have a nominal inside diameter of 3.81 cm. A random sample of 25 bearings is selected and the average inside diameter of these bearings is 3.8037 cm. Bearing diameter is known to be normally distributed with standard deviation σ 0.03 cm. (a) Compute a 95%-confidence interval for the mean inside diameter. (b) Test the hypothesis H0 : μ = 3.81 versus H1 : μ关3.81 using α-001. What is the...
A group of researchers wants to estimate the true mean skidding distance along a new road in a certain forest. The skidding distances (in meters) were measured at 20 randomly selected road sites. These values are given in the accompanying table. Complete parts a through d. 487 350 458 196 289 407 571 438 549 382 300 435 184 260 275 405 313 311 141 426 a. Estimate the true mean skidding distance for the road with a 95 %...