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35 12 A milk display case at a grocery store is stocked with cartons of regular milk and soy milk, in both normal calorie and lighter calorie options. The number of cartons of each type is divided according to the following table. Let R-the event that the carton contains regular milk, S-the event that the carton contains soy milk, N=the event that the carton has normal caloric content, and L=the event that the carton has lighter caloric content A carton is chosen at random. Complete parts (a) through (f) below. Normal Calorio Low Calorie Regular Soy a. Find P(RON) and PIRUN). First determine the formula to use to find P(RON). Let C be the sample space. PIRON) PIRON)-(Simplify your answer.) Determine the formula to use to find P(RUN) PIRUN PIRUN)-(Simplify your answer.) b. Find PILOS) and PLUS). PILS)-(Simplify your answer.) PLUS)-(Simplify your answer.) c. Find the odds in favor of Roccurring, First write an expression for the desired odds. Select all that apply. A. PIR):(1-PR)) C. (1-P(R): P(R) E. P(R): (1 - PAR) The odds in favor of occurring, in lowest terms, are 0 (Type whole numbers.) B. PIR): PIR') OD. PIR'):P(R) F. 1-P(R):PIR) d. Find the odds against L occurring First write an expression for the desired odds. Select all that apply. A. 1 - PL):PL) C. PL'):PL) E. (1-PIL')):PL) B. PL): (1 - P(L)) OD. P(L): (1 - P(L') OF. PIL):PL) The odds against occurring, in lowest terms, are 0:0 (Type whole numbers.) e. Find the odds in favor of ROL occurring First write an expression for the desired odds. Select all that apply. A. (1-PRAL)):PROL) C. PROL): (1-PEROL')) E PROL):(1-PIROL)) B. PEROL)):P(ROL) D. (1-PCR OL))):PROL) OF. PROL):P(ROL)) The adds in favor of ROL occurring, in lowest terms, are on (Type whole numbers.) f. Find the odds against SUN occurring. First write an expression for the desired odds. Select all that apply. A. P((SUN)"):P(SUN) OC. (1-P((SUN)"))=P(SUN) DE PISUN):P((SUN)) The adds against S U N occurring, in lowest terms, are 0 (Type whole number.) B. PISUN):(1 - P(SUN) D. PSUN): (1-P (SUN")) OF. (1 - P(SUN)):P(SUN)

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Answer 1

(1) PCR ON) = IRON) Ich 35. = P(RON) ~ Co. 443] 35+ 12 +21 +11 PCRUN) IRUNI I CI 35+12+ 21 35+12 + 4 +11 68 ~ 10.861 -> P(RUN) 79 (6) P (LAS) No.139 79 12+11 + 1 49. 79 79 P CLUS) 0.557 (c) The odds in favour of R occurring i A. PCR) : (1-PCR)) P(Ⓡ): (1- P(Q)) = 35112 35+12 i 1 - 79 79 47: 79-47 47:32 The odd against . L occusing. A. (I-P(L)): PR) (1-P(1)): P(1) - - 127 : 15 6:23 12711 79 979- 23 : 23 -

odds in favor of R12 oleusing. E, PORAL) : (1-. P(ani)) E. こ 12 79 ; (1-12 79 12:29-12 - 12 67 odds against Sunoccusing. (1-P (SUN)) : P(SUN) fo (1- 21+11+35 29 21+11+35 79 79 - 67 D 67 12:167