Question

Question 1 (1 point) Use following diagram to answer the question 000 000 .. Given that left die shows a multiple of 3, what is the probability that right die shows an even number? O 1/4 1/2 2/3 он! E е со

Answer 1

1) Probability that right die shows an even number given that left die is a multiple of 3.

Let, A be the event that the right die shows an even number, B be the event that the left die is a multiple of 3.

n(B) = {(3,1),(3,2),(3,3),(3,4),(3,5),(3,6), (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)} = 12

n( A $\small \cap$ B) = { (3,2), (3,4),(3,6),(6,2),(6,4),(6,6)} = 6

P(AB) P(ANB) P(B)

6/36 12/36 - 12 2

2) A represents the event that the left die is a multiple of 3. P(A) ,

n(A) = {(3,1),(3,2),(3,3),(3,4),(3,5),(3,6), (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)} = 12

n(S) = 36

$\small P(A)=\frac{n(A)}{n(s)}=\frac{12}{36}=\frac{1}{3}$

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