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Multiple Choice Question An engineer wishes to determine the average time (in seconds) required to drill holes in some metal

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Answer #1

Solution :

Given that,

Population standard deviation = \sigma = 30

Margin of error = E = 15

Z\alpha/2 = 2.576

sample size = n = [Z\alpha/2* \sigma / E] 2

n = [2.576 * 30 / 15]2

n = 27

Sample size = n = 27

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