Question

PROBLEM #1 (50 points) A bolt with a nut is used to clamp together a 1-in cast-iron plate and a 2-in steel plate. 1 The bolt is in-13 UNC. 2 (a) Determine a suitable length for the bolt, rounded up to the nearest in. 4 (b) Determine the bolt stiffness. (c) Determine the stiffness of the members

Answer 1

grip length a la Estte las 2t of 3in height of hexagonal nutes H= I 0.4375 in total length - 340.4375 رح 1 304375 inch rounding to nearest 3.5 inch ។ b thread length zd+ 0.25 in Ly= (d 2.48 mm) dz Li= 1+0.25 L7 z 1.25 inch 2 tensile Areas I do as I (05) 01953 in 2 length of undthreaded Posoportion of grip La = 2-LT Id=3.5 -1025 Id = 2.25 inch So threaded Prokion دح e-l-dd = 3-2.25 0.75 in 난 L

E = Now consider 30x10 psi (steel) cast iron E = 14.5x10 psi ki = AE I 0.1419 X30 R (Steen) 0.75 5.676 Mbt in 01963:30 z) 2.6173 mlbt 2.25 R2 CASA) Cunthreaded) so Req (Perised) Series z) z ☆ +ť +2.0172 5.676 - 11.7913 Millalling k for bolk © length of f = { z frusta (271) Chalf of grip length) 2 login distance between the joint line and clotted frastum line O= lde if » 2-1.5 =) 0.5 Outer dia of frustum ad 0.75+ 20 tanson > 1.904 in R for Castiron 0.5774TEX Ex d Inligst+D-d I (Dra) 4155t + B+ d) (D-d) (0-0

Ri - 0.577 4TT (14-5) 0.5 in SCC1.1594) +0.75 -0.5 ] (0.75 +0.5) 7 [1.15510) +0.75 +0.3.] (0.75-D-5 2) 12.268 frustun In K2= 0.577.4177 (30).0-5 (Toiss.(0.5)+1.904-05 ) Col.90470.5 1•65x0.5+1.904+0-5 ] [1.904-05) R2= 210.71 Mbflin 0.577 4T (30)xo-5 k3 In = (larger 1.155 (13)+0.75–0.5 760.7570.5) frustum steel) 1455(15) +0.75 +0.566-75-005) R₂= 22.6 Mbtlin te (series) + Jer ty ki memern bey 1 I 1 22.6 21007) zs it 12.268 ka 7.662 Mibflin 6 member stijn hen.