Question

ILUWUJU spundeaue-LJUJUJU Zoologists are studying weights of captive timberwolves in three countries the United States, England, and Japan. They want to compare the average weights of the captive wolves to see if there is a direm. A random sample of reported taken. Let -0.05. Source of Variation Mean Squares F Square Between Croups 306.46 2 193.23 6.7304 Within Groups 689.04 24 28.71 Total 1.075.5 26 Summary data are in the table below. United States England Japan 10 9 Mean 66.2 60.1 57.2 Standard Deviation 5.9 (a) What is the critical value? (Use a table. Round your answer to two decimal places.) 93753 What is the number of intervals required? (L) Give the interval for the true difference in the mean weights of captive wolves in the United States and Japan (Round your awers to three decimal places.) NE) 15305 G- G-) c) Determine whether the following statement is true or false. The interval (-3.59. 9.399) is significant at a = 0.05. True False Type here to search di 5:58 PM 7/31/2000 O F

Answer 1

At α = 0.05, k = 3, N-K = 24, Q value = 3.53

Critical Range, CV = Q*√((MSW/2)*(1/ni+1/nj))

Comparison	Diff. = (xi - xj)	Critical Range	Confidence interval
			(xi - xj) - CV	(xi - xj) + CV
x̅1-x̅3	9	6.344	2.656	15.344