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Twelve different video games showing substance use were observed and the duration of times of game play in seconds) are liste
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\begin{tabular}{rrr} \hline X & X - mean & (X-mean)\^{}2 \\ \hline 5.004 & 0.6233 & 0.3885 \\ 3.515 & -0.8657 & 0.7494 \\ 3.887 & -0.4937 & 0.2437 \\ 4.609 & 0.2283 & 0.0521 \\ 4.168 & -0.2127 & 0.0452 \\ 4.654 & 0.2733 & 0.0747 \\ 4.446 & 0.0653 & 0.0043 \\ 4.517 & 0.1363 & 0.0186 \\ 4.678 & 0.2973 & 0.0884 \\ 4.42 & 0.0393 & 0.0015 \\ 3.829 & -0.5517 & 0.3044 \\ 4.841 & 0.4603 & 0.2119 \\ \hline \end{tabular} \\Variance(s^2) = \frac{(\sum{x_i - \bar{x}})^2}{n-1} \\\left(\sum{x_i - \bar{x}}\right)^2 = 2.1827 \\n = 12 \\Variance(s^2) = \frac{2.1827}{11} \\Variance(s^2) = 0.1984 \\\text{Standard Deviation(s) = }\sqrt{Variance} \\\text{Standard Deviation(s) = }0.4454

First we find the confidence interval for variance

\\\chi_{\alpha/2, n-1}^2 = \chi_{0.05, 11}^2 = 19.6751 \\\chi_{1-\alpha/2, n-1}^2 = \chi_{0.95, 11}^2 = 4.5748 \\\text{Confidence interval =} \frac{(n-1)s^2}{\chi_{\alpha/2, n-1}^2}, \frac{(n-1)s^2}{\chi_{1-\alpha/2, n-1}^2} \\\text{Required confidence interval = }\left(\frac{(12-1)0.4454^2}{19.6751}, \frac{(12-1)0.4454^2}{4.5748}\right) \\\text{Required confidence interval = }\left(\frac{(11)0.1984}{19.6751}, \frac{(11)0.1984}{4.5748}\right) \\\text{Required confidence interval = (0.1109, 0.477)} \\\text{Taking the square root of the endpoints of this interval we obtain,} \\\text{Required confidence interval = (0.333, 0.6907)} \\0.333 < \sigma < 0.6907

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