Question

An atom in an excited state 2.00ev above the ground state remains in that excited state 2.03 us before moving to the ground state. Calculate the frequency of the emitted photon. Submit Answer Tries 0/10 Calculate the wavelength of the emitted photon. Submit Answer Tries 0/10 Calculate the approximate uncertainty in energy of the photon. Submit Answer Tries 0/10

Answer 1

means by he of energy -is hr=2ev 2еу Is is Q. Giver energy of excited state A&o= 2.0 eV above the Which the energy difference ground level between the excited state and ground state is zev When atom comes from excited to ground state emitting the Proton hop Rev equal to difference of energy of atoms revesls E So hu &, - & = 2 eV (Q) where h Planks constant So ha 4.1357x10 ev-ser zev 8- frequency of emitted b 4.1357 X/ 0V-sec Photon. V = 0.4836 X109 sec 4.836 XIO" seat Bo The Bequency of emitted Photon Ps p=4.848 10 sect (b) using where v=speed of Photon wavelength V= C (speed of light) d d = 3x108 m/sec 0. 6204 XI56 4.836x10/ sec A 0.620355 X10 6203.55 x16 h The wavelength of emitted Proton is d=6203.55 Å (0) To find uncertainty Pn oncertainty Principle V = so of Photon C= 3x10 8. -10 energy , use Heigerberg

A E Oncertainty in energy uncertainty in time.or life time At ~ 16 of stale DE at 7th Where DE OT to 2 DE = t 6.5821X10 -sec 207 2X2:03 x10 sec DE = 1.628 1010 ev At ren2.03 H sec At we=2.03x10 sec h = 6.5841 xlolen-see 2T st The oncertainty in energy of Proton is AE -1.62 X 10" eV