Question

Answers only is fine!

1. Find the critical value z_c necessary to form a confidence interval at the level of confidence shown below. c=0.92

2. Find the margin of error for the given values of​ c, σ​, and n.

c = 0.95​, σ =2.4​, n = 8.1

Level of Confidence.       zc

90%                             1.645

95%                             1.96

99%                             2.575

3. Construct the confidence interval for the population mean μ.

c=0.98​, x=9.5​, σ=0.3​, and n= 52

4. Construct the confidence interval for the population mean μ.
   c=0.95​, x=16.7​, σ=6.0​, and n= 95
5. Find the minimum sample size n needed to estimate μ for the given values of​ c, σ​, and E.

c=0.95​, σ=5.7​, and E=2. Assume that a preliminary sample has at least 30 members.

6. Find the minimum sample size n needed to estimate μ for the given values of​ c, σ​, and E.

c=0.95​, σ=5.6​, and E=2. Assume that a preliminary sample has at least 30 members.

7. You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of $131.00. Assume the population standard deviation is $19.90. Construct a​ 90% confidence interval for the population mean.
8. From a random sample of 49 dates, the mean record high daily temperature in a certain city has a mean of 83.08°F. Assume the population standard deviation is 14.61°F.This creates a 95​% confidence interval for the population mean of (78.99, 87.17). Does it seem possible that the population mean could be greater than 91°​F? Explain.
9. Determine the minimum sample size required when you want to be 90​% confident that the sample mean is within one unit of the population mean and σ=13.8. Assume the population is normally distributed. A 90% confidence level requires a sample size of nothing.

Answer 1

100 de-1-0.92 = 0.08 02=0 2= 0.04 invnom (0.04,0,1) iny Noyn (096,0,1) 1.450686 041 1.7506?6071 Zutical value tal, alipot pey Margin of emst (ME) = Zala ker me at 70.comyidence 2.4 1.64CX 0.4387 1.96X 2.4 JRE me at 9sf confidence 0.5227) at 90%. confidence - 23.545* ha Me FI 0.686 L=1-0.98 937 98./CI = Ã +2%. = 0.02 les 82 -0.01 0.3 9.5 +1.3263 IS imunorm 20.01,0,1) = -3.32674777 inynorm (0.99,0,1)= 21.82634777 9.5 + 0.0968 (9.4032, 9.5968) 16.4 +1.96 sbs 16.7+ 1.2066 = (15.4934 14.9066) 1