Question

Ten artists (of two different experience levels) are exhibiting their paintings in an art gallery. Three have exhibited in previous shows (making them “experienced artists”) and seven have not. If a patron selects three paintings to purchase at random, find the probability of selecting:

(A) the probability of selecting at least 2 experienced artists’ paintings.

(B) the probability of selecting no experienced artists’ paintings.
(C) the probability of selecting some experienced artists’ paintings.

(D) the probability of selecting less than 2 experienced artists’ paintings.

I also have an additional question, is this a binomial, geometric, hypergeometric, Poisson, normal, or a standard normal problem? I'm very confused on how to tell the difference between them.

Answer 1

solution : 10 Since selections are done without replacement it is not Binomial. Hypergeometoia 7 (E) 3(E) E = Experienced artist. A) plat least 2 experienced artist) P(2) + P(3) (3)( + 60 10. (3) B) Plno experienced) = (3)(3) 7 24 3 c) Plsome one experienced): 1 - PlNo experienced, 7 17 24 24 dj Pl Less thon 2 Experienced) = 1- Plat least 2 Experience = 60 - $49 60