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According to traffic engineers. roundabouts, or traffic circles, result in traffic accidents occurring more or less evenly acFirst, stipulate the null and alternative hypotheses........ Ho: TI = .166; H1: T # .166 Ho:4 = 25; H1: 4 # 25 Ho: Independen

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Answer #1

a) As we are testing here whether the traffic accidents occurring more or less are evenly across all intersections, therefore this is a test for independence here. The null and the alternative hypothesis here are obtained as:

H0: Independence
H1: Dependence.

b) The expected frequency for each of the 6 categories here is computed as:
E = 150/6 = 25

The chi square test statistic here is computed as:

1* = [ (0; – E:)! E;

\chi^2 = \sum \frac{8^2 + 3^2 + 6^2 + 5^2 + 3^2 + 7^2}{25} = 7.68

Therefore 7.7 is the required chi square test statistic value here.

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