Question

Previous Problem List Next (1 point) In the game of roulette, a steel ball is rolled onto a wheel that contains 18 red, 18 black, and 2 green slots. If the ball is rolled 29 times, find the probability of the following events. A. The ball falls into the green slots 5 or more times. Probability = B. The ball does not fall into any green slots. Probability = 0.208 C. The ball falls into black slots 11 or more times. Probability = D. The ball falls into red slots 11 or fewer times. Probability = Note: You can earn partial credit on this problem.

Answer 1

Reed Black = 18 green = 2 - Total = 38 PlRed) = 18 -0.47 38 P (Black) = 18 = 0.47 38 Pl Green) = 2 = 0.06 38 A M = np 29 x 0.06 1.74 r = Jn.p.1-e) = Jr9 x0.06x0.44 p(x>,5) By normal approximation- P(X-4 5-4) پر - ک Plz> S-1.74 Pl 27,2.55) |- Pl 242.35)

by 2 table I- 0.9946 0.005 y P ( Ball not fall into green gre slots) - Pl Cree) 0.06 = o.94 Pl Black) = 0.47 n = 29 M = n. p= 29 x 0.47 13.63 o= Jn. p. (1.8) - Jag xo XO.y7X0.53= 2.69 PIX3,11) By Normal approximation- PI X Y », 1-2) P/22, 11-1363 2.69 P127,-0.98)

1- P1 22-0.98) I 0.1635 0.6365 D PlRed) = 0.47 M = n. p = 13.63 =2.69 Plx411) By Noomal approximation- pl Xy alley) P/ 2₂ 11-13.63 2.69 Plz 2-0.98) By 2 table 0.1635 Please like