Solve Equations
109x+131y+83z=4921,x+y+z=49,-2y+z=0 using Elimination
method
Solution:
Total
Equations are 3
109x+131y+83z=4921→(1)
x+y+z=49→(2)
0x-2y+z=0→(3)
Select the
equations (1) and (2), and eliminate the
variable x.
| 109x+131y+83z=4921 | ×1→ | 109x | + | 131y | + | 83z | = | 4921 | |||
| − | |||||||||||
| x+y+z=49 | ×109→ | 109x | + | 109y | + | 109z | = | 5341 | |||
| 22y | - | 26z | = | -420 | →(4) |
Select the
equations (3) and (4), and eliminate the
variable z.
| -2y+z=0 | ×26→ | - | 52y | + | 26z | = | 0 | ||||
| + | |||||||||||
| 22y-26z=-420 | ×1→ | 22y | - | 26z | = | -420 | |||||
| - | 30y | = | -420 | →(5) |
Now use
back substitution method
From
(5)
-30y=-420
⇒y=-420-30=14
From
(3)
-2y+z=0
⇒-2(14)+1z=0
⇒1z-28=0
⇒1z=0+28=28
From
(2)
x+y+z=49
⇒1x+1(14)+1(28)=49
⇒1x+42=49
⇒1x=49-42=7
Solution
using Elimination method.
x=7,y=14,z=28
The company purchased 7 inkjet printers, 14 LCD monitors ,and 28 memory chips
A company is upgrading office technology by purchasing inkjet printers, LCD monitors, and additional memory chips....
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and the cost of each memory chip is $88. The total amount of money
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