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We have a dataset with n= 10 pairs of observations (li, Yi), and n 72 2; = 683, Yi = 813, i=1 72 TE at = 47,405, xiyi = 56, 0
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Answer #1
n= 10
Σx= 683
Σx2 = 47405
Σy = 813
Σy2 = 66731
Σxy= 56089
SSx=Σx2-(Σx)2/n= 756.1000
SSy=Σy2-(Σy)2/n= 634.1000
SP=Σxy-(ΣxΣy)/n= 561.1000
SST=Syy= 634.1
SSE =Syy-(Sxy)2/Sxx= 217.7090
SSR =(Sxy)2/Sxx = 416.3910
b1= SSxy/Sx = 0.7421
σ̂2=SSE/(n-2)= 27.2136
sb1 =σ̂/√SSx = 0.1897
for 99% confidence and n-2 degree of freedom critical t = 3.355
lower bound =b1-t*sb1= 0.1056
upper bound =b1+t*sb1= 1.3786

therefore 99% confidence interval for the slope =(0.1056 , 1.3786)

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