a_)
| Null hypothesis:Ho: severity of condition and biologics/biosimilar are independent. |
| alternate hypothesis:Ha: severity of condition and biologics/biosimilar are dependent. |
b)
| degree of freedom(df) =(rows-1)*(columns-1)=(3-1)*(4-1)= | 6 | |
c)below is expected value table:
| Expected | Ei=row total*column total/grand total | Biologics | Biosimilar 1 | Biosimilar 2 | Biosimilar 3 | Total |
| Absent | 541.2000 | 212.9600 | 92.4000 | 473.4400 | 1320 | |
| Mild | 43.0500 | 16.9400 | 7.3500 | 37.6600 | 105 | |
| Severe | 30.7500 | 12.1000 | 5.2500 | 26.9000 | 75 | |
| total | 615 | 242 | 105 | 538 | 1500 |
d)
| Applying chi square test of independence: |
| chi square χ2 | =(Oi-Ei)2/Ei | Biologics | Biosimilar 1 | Biosimilar 2 | Biosimilar 3 | Total |
| Absent | 0.006 | 0.018 | 0.062 | 0.014 | 0.1002 | |
| Mild | 0.021 | 1.511 | 0.057 | 1.178 | 2.7677 | |
| Severe | 0.246 | 0.794 | 0.583 | 0.625 | 2.2484 | |
| total | 0.2729 | 2.3237 | 0.7032 | 1.8165 | 5.1163 | |
| test statistic X2= | 5.1163 | |||||
e)
| since test statistic does not falls in rejection region we fail to reject null hypothesis |
f)
| we do not have have sufficient evidence to reject the hypothesis that severity of condition and biologics/biosimilar are independent. |
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