Question

This exercise is also from C++

How do I even figure this out? please help me solve so I can get the answer correctly!

Question 28 10 pts (SHORT ANSWER) Define a function named findEvenOrOdd that has 1 int parameter: num. When the function is called, it should use an if/else statement -OR- conditional expression to determine whether the variable num is an even or odd number and display appropriate message as follows: • If the value in num is an even number, the program will output the message: "XX is an EVEN number", where XX is the value in the variable num • Else, the program will output the message: "XX is an ODD number", where XX is the value in the variable num Example 1, If we called the function findEvenOrOdd(6) then, the output should display as follows: 6 is an EVEN number Example 2. If we called the function findEvenOrOdd(11) then, the output should display as follows: 11 is an ODD number B I J A AI = = = = = x x = = - V 11 12pt Paragraph O words

Answer 1

CODE:

#include <iostream>

using namespace std;

// function

void findEvenOrOdd(int num){

  // check if even or not

  if(num%2==0)

    cout<<num<<" is an EVEN number"<<endl;

  else

    cout<<num<<" is an ODD number"<<endl;

}

// main method

int main() {

findEvenOrOdd(6);

findEvenOrOdd(11);

}

main.cpp 1 #include <iostream> 2 using namespace std; 3 4 // function 5 void findEvenOrodd(int num) { 6 // check if even or not 7 if(num%2==0) 8 cout<<num<<" is an EVEN number"<<endl; 9 else 10 cout<<num<<" is an ODD number"<<endl; 11 } 12 13 // main method 14 int main() { 15 findEvenorodd(6); 16 findEvenorodd(11); 17 18 }

OUTPUT:

6 is an EVEN number 11 is an ODD number

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